What is the inverse of g(x)=(5x-1)/(4x+7) ?

The inverse of g(x)=(5x-1)/(4x+7) is (-1-7x)/(4x-5)

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inverse of g(x)=(5x-1)/(4x+7)

inverse

g (x) = \frac{5 x - 1}{4 x + 7}

\frac{- 1 - 7 x}{4 x - 5}

Solution steps

y = \frac{5 x - 1}{4 x + 7}

Replace

x

with

y

x = \frac{5 y - 1}{4 y + 7}

Solve for

y, x = \frac{5 y - 1}{4 y + 7}

\frac{- 1 - 7 x}{4 x - 5}

f (x) = \frac{( x - 2000 )}{100}

f (x) = arcsin (3 x - 1)

f (x) = \frac{2 x + 1}{x - 1}, x \neq = 1

f (x) = \frac{1}{7} x - 7

\frac{( 2 S - 3 )}{S ^{2} + S - 2}

What is the inverse of g(x)=(5x-1)/(4x+7) ?
The inverse of g(x)=(5x-1)/(4x+7) is (-1-7x)/(4x-5)