What is the inverse of ((2S-3))/(S^2+S-2) ?

The inverse of ((2S-3))/(S^2+S-2) is (-S+2+sqrt(9S^2-16S+4))/(2S),(-S+2-sqrt(9S^2-16S+4))/(2S)

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inverse of ((2S-3))/(S^2+S-2)

inverse

\frac{( 2 S - 3 )}{S ^{2} + S - 2}

\frac{- S + 2 + 9 S ^{2} - 16 S + 4}{2 S}, \frac{- S + 2 - 9 S ^{2} - 16 S + 4}{2 S}

Solution steps

y = \frac{2 S - 3}{S ^{2} + S - 2}

Replace

S

with

y

S = \frac{2 y - 3}{y ^{2} + y - 2}

Solve for

y, S = \frac{2 y - 3}{y ^{2} + y - 2}

\frac{- S + 2 + 9 S ^{2} - 16 S + 4}{2 S}, \frac{- S + 2 - 9 S ^{2} - 16 S + 4}{2 S}

y = x + 11 + 5

81 - \frac{2}{x}

\frac{2}{s} - \frac{2}{s + 1}

f (x) = - 2^{x + 1} + 4

What is the inverse of ((2S-3))/(S^2+S-2) ?
The inverse of ((2S-3))/(S^2+S-2) is (-S+2+sqrt(9S^2-16S+4))/(2S),(-S+2-sqrt(9S^2-16S+4))/(2S)