What is the inverse of f(x)=sqrt(ln(x^3-7)) ?

The inverse of f(x)=sqrt(ln(x^3-7)) is cube root of e^{x^2}+7

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inverse of f(x)=sqrt(ln(x^3-7))

inverse

f (x) = ln (x^{3} - 7)

Solution steps

y = ln (x^{3} - 7)

Replace

x

with

y

x = ln (y^{3} - 7)

Solve for

y, x = ln (y^{3} - 7)

tan (\frac{12}{145})

- 2 x^{2} + 8 x - 4

(1 + n) u (n)

f (x) = f (x) = - \frac{5}{3} x - 5

g (x) = 36 x^{2}

What is the inverse of f(x)=sqrt(ln(x^3-7)) ?
The inverse of f(x)=sqrt(ln(x^3-7)) is cube root of e^{x^2}+7