What is the inverse of d/d (\sqrt[3]{1/(4x^2)}) ?

The inverse of d/d (\sqrt[3]{1/(4x^2)}) is (sqrt(x))/(2x^2),-(sqrt(x))/(2x^2)

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inverse of d/d (\sqrt[3]{1/(4x^2)})

inverse

\frac{x}{2 x ^{2}}, - \frac{x}{2 x ^{2}}

Solution steps

Replace

x

with

y

Solve for

\frac{x}{2 x ^{2}}, - \frac{x}{2 x ^{2}}

7 + tan (π x)

f (x) = y^{2} - 8 y

cos (100 f)

f (\frac{x + 2020}{x + 2022}) = x + 2021

\frac{4 x ^{2} + 5}{6 x + 4}

What is the inverse of d/d (\sqrt[3]{1/(4x^2)}) ?
The inverse of d/d (\sqrt[3]{1/(4x^2)}) is (sqrt(x))/(2x^2),-(sqrt(x))/(2x^2)