What is the inverse of f(x)=((1-3x))/(2x+1) ?

The inverse of f(x)=((1-3x))/(2x+1) is (1-x)/(2x+3)

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inverse of f(x)=((1-3x))/(2x+1)

inverse

f (x) = \frac{( 1 - 3 x )}{2 x + 1}

\frac{1 - x}{2 x + 3}

Solution steps

y = \frac{1 - 3 x}{2 x + 1}

Replace

x

with

y

x = \frac{1 - 3 y}{2 y + 1}

Solve for

y, x = \frac{1 - 3 y}{2 y + 1}

\frac{1 - x}{2 x + 3}

f (p) = 200 - p

f (x) = \frac{4 x}{3 x + 2}

f (x) = 1 - \frac{58}{80 ( 1 - x )}

y = 50 - 40 x + 15 x^{2}

f (x) = 4 e^{- x} + 2

What is the inverse of f(x)=((1-3x))/(2x+1) ?
The inverse of f(x)=((1-3x))/(2x+1) is (1-x)/(2x+3)