What is the inverse of y=50-40x+15x^2 ?

The inverse of y=50-40x+15x^2 is (40+sqrt(60x-1400))/(30),(40-sqrt(60x-1400))/(30)

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inverse of y=50-40x+15x^2

inverse

y = 50 - 40 x + 15 x^{2}

\frac{40 + 60 x - 1400}{30}, \frac{40 - 60 x - 1400}{30}

Solution steps

y = 50 - 40 x + 15 x^{2}

Replace

x

with

y

x = 50 - 40 y + 15 y^{2}

Solve for

y, x = 50 - 40 y + 15 y^{2}

\frac{40 + 60 x - 1400}{30}, \frac{40 - 60 x - 1400}{30}

f (x) = 4 e^{- x} + 2

f (x) = 9 - t - 3 + t

\frac{s ^{2} + 6 s + 8}{s ^{2} + 2}

{- x : x \leq 0}

+ ln (\frac{x + 1}{2})

What is the inverse of y=50-40x+15x^2 ?
The inverse of y=50-40x+15x^2 is (40+sqrt(60x-1400))/(30),(40-sqrt(60x-1400))/(30)