What is the inverse of f(x)=sqrt(9-t)-sqrt(3+t) ?

The inverse of f(x)=sqrt(9-t)-sqrt(3+t) is (6+tsqrt(-t^2+24))/2 ,(6-tsqrt(-t^2+24))/2

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inverse of f(x)=sqrt(9-t)-sqrt(3+t)

inverse

f (x) = 9 - t - 3 + t

\frac{6 + t - t ^{2} + 24}{2}, \frac{6 - t - t ^{2} + 24}{2}

Solution steps

x = 9 - t - 3 + t

Replace

t

with

x

t = 9 - x - 3 + x

Solve for

x, t = 9 - x - 3 + x

\frac{6 + t - t ^{2} + 24}{2}, \frac{6 - t - t ^{2} + 24}{2}

\frac{s ^{2} + 6 s + 8}{s ^{2} + 2}

{- x : x \leq 0}

+ ln (\frac{x + 1}{2})

f (x) = e 3^{z} = 15

f (x) = - 2 (x + 1)^{2 + 3}

What is the inverse of f(x)=sqrt(9-t)-sqrt(3+t) ?
The inverse of f(x)=sqrt(9-t)-sqrt(3+t) is (6+tsqrt(-t^2+24))/2 ,(6-tsqrt(-t^2+24))/2