What is the inverse of f(x)=(x-1)/(2x+9) ?

The inverse of f(x)=(x-1)/(2x+9) is (-1-9x)/(2x-1)

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inverse of f(x)=(x-1)/(2x+9)

inverse

f (x) = \frac{x - 1}{2 x + 9}

\frac{- 1 - 9 x}{2 x - 1}

Solution steps

y = \frac{x - 1}{2 x + 9}

Replace

x

with

y

x = \frac{y - 1}{2 y + 9}

Solve for

y, x = \frac{y - 1}{2 y + 9}

\frac{- 1 - 9 x}{2 x - 1}

\frac{4}{2 x ^{2} - 11 x + 5}

2 x - 8

- \frac{x - 1}{3} - 2

f (x) = 6 \cdot x \cdot (x - 1) + 1

f (x) = 2 x^{\frac{1}{5}} - 5

What is the inverse of f(x)=(x-1)/(2x+9) ?
The inverse of f(x)=(x-1)/(2x+9) is (-1-9x)/(2x-1)