What is the inverse of f(x)=(-3x-2)/(2x-1) ?

The inverse of f(x)=(-3x-2)/(2x-1) is (-2+x)/(2x+3)

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inverse of f(x)=(-3x-2)/(2x-1)

inverse

f (x) = \frac{- 3 x - 2}{2 x - 1}

\frac{- 2 + x}{2 x + 3}

Solution steps

y = \frac{- 3 x - 2}{2 x - 1}

Replace

x

with

y

x = \frac{- 3 y - 2}{2 y - 1}

Solve for

y, x = \frac{- 3 y - 2}{2 y - 1}

\frac{- 2 + x}{2 x + 3}

y = \frac{3 x + 2}{2 x - 5}

f (x) = \frac{3}{ln ( x ) + 5}

\frac{3 x ^{2} + 9 x - 12}{x ^{2} + 13 x + 36}

f (x) = \frac{3 - x}{2 x + 5}

f (x) = \frac{2 x + 7}{x - 2}

What is the inverse of f(x)=(-3x-2)/(2x-1) ?
The inverse of f(x)=(-3x-2)/(2x-1) is (-2+x)/(2x+3)