What is the inverse of f(x)=r(3)=-5x3-7x2-10x-5 ?

The inverse of f(x)=r(3)=-5x3-7x2-10x-5 is -(x+5)/(39)

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inverse of f(x)=r(3)=-5x3-7x2-10x-5

inverse

f (x) = r (3) = - 5 x 3 - 7 x 2 - 10 x - 5

- \frac{x + 5}{39}

Solution steps

r = - 5 x \cdot 3 - 7 x \cdot 2 - 10 x - 5

Replace

x

with

r

x = - 5 r \cdot 3 - 7 r \cdot 2 - 10 r - 5

Solve for

r, x = - 5 r 3 - 7 r 2 - 10 r - 5

- \frac{x + 5}{39}

f (x) = - 5^{2} + 3 t + 3

f (x) = 4 - 1 - x^{2}

49 + 2.3 (h - 61)

f (x) = 7^{(x - 8)} + 10

What is the inverse of f(x)=r(3)=-5x3-7x2-10x-5 ?
The inverse of f(x)=r(3)=-5x3-7x2-10x-5 is -(x+5)/(39)