What is the inverse of f(x)=0.2log_{7}(3x+2)-9 ?

The inverse of f(x)=0.2log_{7}(3x+2)-9 is (16807^{x+9}-2)/3

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inverse of f(x)=0.2log_{7}(3x+2)-9

inverse

f (x) = 0.2 lo g_{7} (3 x + 2) - 9

\frac{1680 7 ^{x + 9} - 2}{3}

Solution steps

y = 0.2 lo g_{7} (3 x + 2) - 9

Replace

x

with

y

x = 0.2 lo g_{7} (3 y + 2) - 9

Solve for

y, x = 0.2 lo g_{7} (3 y + 2) - 9

\frac{1680 7 ^{x + 9} - 2}{3}

\frac{7}{4 ^{3} x ^{2}}

\frac{8 - 5 x}{3 + 2 x}

f (x) = 1 + 2 ln (x + 3)

f (x) = 4^{x - 1} + 1

f (x) = 5 x^{4} - 5

What is the inverse of f(x)=0.2log_{7}(3x+2)-9 ?
The inverse of f(x)=0.2log_{7}(3x+2)-9 is (16807^{x+9}-2)/3