What is the inverse of f(x)=f(x)= 2/5 x^3-4 ?

The inverse of f(x)=f(x)= 2/5 x^3-4 is cube root of (5x+20)/2

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inverse of f(x)=f(x)= 2/5 x^3-4

inverse

f (x) = f (x) = \frac{2}{5} x^{3} - 4

Solution steps

y = \frac{2}{5} x^{3} - 4

Replace

x

with

y

x = \frac{2}{5} y^{3} - 4

Solve for

y, x = \frac{2}{5} y^{3} - 4

f (x) = (\frac{1}{0.15 x + 1})

- 3 (\frac{1}{2})^{x} - 6

f (x) = - 6 (- 6 x)

\frac{6}{s ^{2} + 4}

f (x) = 3 arccos (x)

What is the inverse of f(x)=f(x)= 2/5 x^3-4 ?
The inverse of f(x)=f(x)= 2/5 x^3-4 is cube root of (5x+20)/2