What is the inverse of f(x)=2^{sqrt(x)} ?

The inverse of f(x)=2^{sqrt(x)} is (ln^2(x))/(ln^2(2))

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inverse of f(x)=2^{sqrt(x)}

inverse

f (x) = 2^{x}

\frac{ln ^{2} ( x )}{ln ^{2} ( 2 )}

Solution steps

y = 2^{x}

Replace

x

with

y

x = 2^{y}

Solve for

y, x = 2^{y}

\frac{ln ^{2} ( x )}{ln ^{2} ( 2 )}

4 cos (3 x - \frac{π}{2})

f (x) = 7 + x

h (x) = \frac{10 x}{8 x - 3}

f (x) = \frac{4 + x ^{2}}{2}

f (x) = \frac{x}{3} + 7

What is the inverse of f(x)=2^{sqrt(x)} ?
The inverse of f(x)=2^{sqrt(x)} is (ln^2(x))/(ln^2(2))