What is the inverse of f(x)=((4-(x+a)))/(3-(x+a)) ?

The inverse of f(x)=((4-(x+a)))/(3-(x+a)) is (4-a-3x+ax)/(-x+1)

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inverse of f(x)=((4-(x+a)))/(3-(x+a))

inverse

f (x) = \frac{( 4 - ( x + a ) )}{3 - ( x + a )}

\frac{4 - a - 3 x + a x}{- x + 1}

Solution steps

y = \frac{4 - ( x + a )}{3 - ( x + a )}

Replace

x

with

y

x = \frac{4 - ( y + a )}{3 - ( y + a )}

Solve for

y, x = \frac{4 - ( y + a )}{3 - ( y + a )}

\frac{4 - a - 3 x + a x}{- x + 1}

\frac{3 x - 5}{9 x + 4}

y = \frac{- 6}{9 - x ^{2}}

f (x) = (x - 3)

f (x) = \frac{x + 4}{x - 9}

f (x) = \frac{e ^{x}}{e ^{x} + 3}

What is the inverse of f(x)=((4-(x+a)))/(3-(x+a)) ?
The inverse of f(x)=((4-(x+a)))/(3-(x+a)) is (4-a-3x+ax)/(-x+1)