What is the inverse of h(x)=((x+3))/((x-2)) ?

The inverse of h(x)=((x+3))/((x-2)) is (3+2x)/(x-1)

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inverse of h(x)=((x+3))/((x-2))

inverse

h (x) = \frac{( x + 3 )}{( x - 2 )}

\frac{3 + 2 x}{x - 1}

Solution steps

y = \frac{x + 3}{x - 2}

Replace

x

with

y

x = \frac{y + 3}{y - 2}

Solve for

y, x = \frac{y + 3}{y - 2}

\frac{3 + 2 x}{x - 1}

ln (1 - J)

y = 7 - x

f (x) = \frac{7 x - 8}{x + 7}

2 - 3^{2 + x}

\frac{( 2 x - 1 ) ^{2}}{e}

What is the inverse of h(x)=((x+3))/((x-2)) ?
The inverse of h(x)=((x+3))/((x-2)) is (3+2x)/(x-1)