What is the inverse of ((z-8)^2)/(z^2-64) ?

The inverse of ((z-8)^2)/(z^2-64) is (-8-8z)/(z-1)

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inverse of ((z-8)^2)/(z^2-64)

inverse

\frac{( z - 8 ) ^{2}}{z ^{2} - 64}

\frac{- 8 - 8 z}{z - 1}

Solution steps

y = \frac{( z - 8 ) ^{2}}{z ^{2} - 64}

Replace

z

with

y

z = \frac{( y - 8 ) ^{2}}{y ^{2} - 64}

Solve for

y, z = \frac{( y - 8 ) ^{2}}{y ^{2} - 64}

\frac{- 8 - 8 z}{z - 1}

g (x) = \frac{4 x}{7 x - 5}

f (x) = 3 + 4 x - 3

4 - 6 (4 - 1)

f (x) = 2 sin (x) - 7

\frac{x - 4 x}{x - 4}

What is the inverse of ((z-8)^2)/(z^2-64) ?
The inverse of ((z-8)^2)/(z^2-64) is (-8-8z)/(z-1)