What is the inverse of f(x)=(x^3-4)^5 ?

The inverse of f(x)=(x^3-4)^5 is cube root of \sqrt[5]{x}+4

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inverse of f(x)=(x^3-4)^5

inverse

f (x) = (x^{3} - 4)^{5}

Solution steps

y = (x^{3} - 4)^{5}

Replace

x

with

y

x = (y^{3} - 4)^{5}

Solve for

y, x = (y^{3} - 4)^{5}

lo g_{10} (x + 1) - 3

f (x) = x^{2} = 8 x + 20

f (x) = (2 x + 1)^{3} - 2

lo g_{10} (x - 5) + 2

f (x) = 60 - 4 x

What is the inverse of f(x)=(x^3-4)^5 ?
The inverse of f(x)=(x^3-4)^5 is cube root of \sqrt[5]{x}+4