What is the inverse of (1000-x^2)/(4x) ?

The inverse of (1000-x^2)/(4x) is -2(x+sqrt(x^2+250)),-2(x-sqrt(x^2+250))

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inverse of (1000-x^2)/(4x)

inverse

\frac{1000 - x ^{2}}{4 x}

- 2 (x + x^{2} + 250), - 2 (x - x^{2} + 250)

Solution steps

y = \frac{1000 - x ^{2}}{4 x}

Replace

x

with

y

x = \frac{1000 - y ^{2}}{4 y}

Solve for

y, x = \frac{1000 - y ^{2}}{4 y}

- 2 (x + x^{2} + 250), - 2 (x - x^{2} + 250)

y = \frac{1}{3} x - 2

f (x) = \frac{( x + 1 )}{( x + 3 )}

lo g_{10} (x - 5) - 3

f (x) = \frac{1}{7} (x^{3} + 5)

\frac{2 ^{x} - 1}{2 ^{x} + 1}

What is the inverse of (1000-x^2)/(4x) ?
The inverse of (1000-x^2)/(4x) is -2(x+sqrt(x^2+250)),-2(x-sqrt(x^2+250))