What is the inverse of sqrt((-3x-11)/(2x-8)) ?

The inverse of sqrt((-3x-11)/(2x-8)) is (-11+8x^2)/(2x^2+3)

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inverse of sqrt((-3x-11)/(2x-8))

inverse

\frac{- 3 x - 11}{2 x - 8}

\frac{- 11 + 8 x ^{2}}{2 x ^{2} + 3}

Solution steps

y = \frac{- 3 x - 11}{2 x - 8}

Replace

x

with

y

x = \frac{- 3 y - 11}{2 y - 8}

Solve for

y, x = \frac{- 3 y - 11}{2 y - 8}

\frac{- 11 + 8 x ^{2}}{2 x ^{2} + 3}

f (x) = 2 x^{7} + 7

f (x) = - 5 (- 5 x - 9)^{2} - 6, x \geq - 95

f (x) = 1 + 2 (1 - \frac{2}{x + 1})

cos (3 x + 2 π) + 3

What is the inverse of sqrt((-3x-11)/(2x-8)) ?
The inverse of sqrt((-3x-11)/(2x-8)) is (-11+8x^2)/(2x^2+3)