What is the inverse of f(x)=1+2(1-2/(x+1)) ?

The inverse of f(x)=1+2(1-2/(x+1)) is (-x-1)/(x-3)

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inverse of f(x)=1+2(1-2/(x+1))

inverse

f (x) = 1 + 2 (1 - \frac{2}{x + 1})

\frac{- x - 1}{x - 3}

Solution steps

y = 1 + 2 (1 - \frac{2}{x + 1})

Replace

x

with

y

x = 1 + 2 (1 - \frac{2}{y + 1})

Solve for

y, x = 1 + 2 (1 - \frac{2}{y + 1})

\frac{- x - 1}{x - 3}

cos (3 x + 2 π) + 3

f (x) = \frac{1}{3} x^{2} - 4

y = 4 - \frac{1}{( x + 1 ) ^{2}}

f (x) = \frac{2 x + 3}{5 x - 1}, x \neq = \frac{1}{5}

What is the inverse of f(x)=1+2(1-2/(x+1)) ?
The inverse of f(x)=1+2(1-2/(x+1)) is (-x-1)/(x-3)