What is the inverse of 1/(s^2+2s-2) ?

The inverse of 1/(s^2+2s-2) is (-s+sqrt(s(3s+1)))/s ,-(s+sqrt(s(3s+1)))/s

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inverse of 1/(s^2+2s-2)

inverse

\frac{1}{s ^{2} + 2 s - 2}

\frac{- s + s ( 3 s + 1 )}{s}, - \frac{s + s ( 3 s + 1 )}{s}

Solution steps

y = \frac{1}{s ^{2} + 2 s - 2}

Replace

s

with

y

s = \frac{1}{y ^{2} + 2 y - 2}

Solve for

y, s = \frac{1}{y ^{2} + 2 y - 2}

\frac{- s + s ( 3 s + 1 )}{s}, - \frac{s + s ( 3 s + 1 )}{s}

f (x) = (x - 6) 2

ln (- 11.182)

f (t) = 1 + 2 t^{3}

y = (2 tan^{3} (2 x) - 1)^{\frac{1}{3}}

- \frac{1}{( 4 t - 7 ) ^{2}}

What is the inverse of 1/(s^2+2s-2) ?
The inverse of 1/(s^2+2s-2) is (-s+sqrt(s(3s+1)))/s ,-(s+sqrt(s(3s+1)))/s