What is the inverse of f(x)=(x+4)^2-3,x>=-4 ?

The inverse of f(x)=(x+4)^2-3,x>=-4 is sqrt(x+3)-4,-sqrt(x+3)-4

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inverse of f(x)=(x+4)^2-3,x>=-4

inverse

f (x) = (x + 4)^{2} - 3, x \geq - 4

x + 3 - 4, - x + 3 - 4

Solution steps

y = (x + 4)^{2} - 3

Replace

x

with

y

x = (y + 4)^{2} - 3

Solve for

y, x = (y + 4)^{2} - 3

x + 3 - 4, - x + 3 - 4

x^{2} - 16, x \geq 0

4

1 - 3 x + 1 - 5 x

\frac{x ^{2} - 8}{x - 3}

f (x) = (\frac{3 x + 4}{x - 3})

What is the inverse of f(x)=(x+4)^2-3,x>=-4 ?
The inverse of f(x)=(x+4)^2-3,x>=-4 is sqrt(x+3)-4,-sqrt(x+3)-4