What is the inverse of f(x)=y-5= 1/2 (x+16)^2 ?

The inverse of f(x)=y-5= 1/2 (x+16)^2 is sqrt(2)sqrt(x)-16,-sqrt(2)sqrt(x)-16

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inverse of f(x)=y-5= 1/2 (x+16)^2

inverse

f (x) = y - 5 = \frac{1}{2} (x + 16)^{2}

2 x - 16, - 2 x - 16

Solution steps

y = \frac{1}{2} (x + 16)^{2}

Replace

x

with

y

x = \frac{1}{2} (y + 16)^{2}

Solve for

y, x = \frac{1}{2} (y + 16)^{2}

2 x - 16, - 2 x - 16

f (x) = 5 (x + 10)^{\frac{1}{3}} - 8

f (x) = \frac{( - 2 x - 5 )}{- 8 x + 5}

y = 2 x^{2} - 5 x

5 x^{2} + 5 x

f (x) = 3 x^{2} - 4.03

What is the inverse of f(x)=y-5= 1/2 (x+16)^2 ?
The inverse of f(x)=y-5= 1/2 (x+16)^2 is sqrt(2)sqrt(x)-16,-sqrt(2)sqrt(x)-16