What is the inverse of f(x)=15x^2-38 ?

The inverse of f(x)=15x^2-38 is sqrt((x+38)/(15)),-sqrt((x+38)/(15))

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inverse of f(x)=15x^2-38

inverse

f (x) = 15 x^{2} - 38

\frac{x + 38}{15}, - \frac{x + 38}{15}

Solution steps

y = 15 x^{2} - 38

Replace

x

with

y

x = 15 y^{2} - 38

Solve for

y, x = 15 y^{2} - 38

\frac{x + 38}{15}, - \frac{x + 38}{15}

f (x) = 20 cos (5 x + 7)

f (x) = (- 12 x - 17)^{2}

\frac{2}{s - 3}

\frac{( x ^{2} )}{4 x}

f (x) = \frac{5 x - 1}{- 3 x + 2}

What is the inverse of f(x)=15x^2-38 ?
The inverse of f(x)=15x^2-38 is sqrt((x+38)/(15)),-sqrt((x+38)/(15))