What is the inverse of f(x)=x^2-4x-8 ?

The inverse of f(x)=x^2-4x-8 is 2+sqrt(x+12),2-sqrt(x+12)

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inverse of f(x)=x^2-4x-8

inverse

f (x) = x^{2} - 4 x - 8

2 + x + 12, 2 - x + 12

Solution steps

y = x^{2} - 4 x - 8

Replace

x

with

y

x = y^{2} - 4 y - 8

Solve for

y, x = y^{2} - 4 y - 8

2 + x + 12, 2 - x + 12

y = \frac{1}{2} x - 1

f (x) = \frac{4 x}{7 x - 6}

f (x) = - 2 x^{2} - 4 x - 5

\frac{30 x + 20}{x}

What is the inverse of f(x)=x^2-4x-8 ?
The inverse of f(x)=x^2-4x-8 is 2+sqrt(x+12),2-sqrt(x+12)