What is the inverse of-tan((4pi)/9) ?

The inverse of-tan((4pi)/9) is None

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inverse of-tan((4pi)/9)

inverse

- tan (\frac{4 π}{9})

None

Solution steps

Solve for

tan (\frac{4 π}{9}), y = - tan (\frac{4 π}{9})

tan (\frac{4 π}{9}) = - y

tan (a) = b \Rightarrow a = arctan (b)

\frac{4 π}{9} = arctan (- y)

Solve for

x, \frac{4 π}{9} = arctan (- y)

Since the function is a constant function it has no inverse function

None

- lo g_{4} (x - 1) + 2

f (x) = \frac{3 - 2 x}{2 x + 2}

3 lo g_{3} (\frac{1}{2} x - 1) + 1

tan (\frac{π}{2})

f (x) = \frac{x}{4} + \frac{4}{9}