What is the inverse of 3log_{3}(1/2 x-1)+1 ?

The inverse of 3log_{3}(1/2 x-1)+1 is 2*3^{(x-1)/3}+2

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inverse of 3log_{3}(1/2 x-1)+1

inverse

3 lo g_{3} (\frac{1}{2} x - 1) + 1

2 \cdot 3^{\frac{x - 1}{3}} + 2

Solution steps

y = 3 lo g_{3} (\frac{1}{2} x - 1) + 1

Replace

x

with

y

x = 3 lo g_{3} (\frac{1}{2} y - 1) + 1

Solve for

y, x = 3 lo g_{3} (\frac{1}{2} y - 1) + 1

2 \cdot 3^{\frac{x - 1}{3}} + 2

tan (\frac{π}{2})

f (x) = \frac{x}{4} + \frac{4}{9}

f (x) = (\frac{45}{x ^{2} + 9})

f (x) = \frac{1 + 5 x}{7 - 3 x}

f (x) = x^{2} + 9 x + 38

What is the inverse of 3log_{3}(1/2 x-1)+1 ?
The inverse of 3log_{3}(1/2 x-1)+1 is 2*3^{(x-1)/3}+2