What is the inverse of f(x)=(x-5)^2,[5,infinity ] ?

The inverse of f(x)=(x-5)^2,[5,infinity ] is sqrt(x)+5,-sqrt(x)+5

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inverse of f(x)=(x-5)^2,[5,infinity ]

inverse

f (x) = (x - 5)^{2}, [5, \infty]

x + 5, - x + 5

Solution steps

y = (x - 5)^{2}

Replace

x

with

y

x = (y - 5)^{2}

Solve for

y, x = (y - 5)^{2}

x + 5, - x + 5

f (x) = \frac{5 x + 2}{2 x - 2}

f (x) = 9 (- 8 x + 8)^{2} + 10

y = 2.5 x + 5.5

f (x) = f (x) = x - 2

f (x) = f (x) = x - 3

What is the inverse of f(x)=(x-5)^2,[5,infinity ] ?
The inverse of f(x)=(x-5)^2,[5,infinity ] is sqrt(x)+5,-sqrt(x)+5