What is the inverse of 13/49 x^2-26/7 x+18 ?

The inverse of 13/49 x^2-26/7 x+18 is (182+sqrt(2548x-12740))/(26),(182-sqrt(2548x-12740))/(26)

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inverse of 13/49 x^2-26/7 x+18

inverse

\frac{13}{49} x^{2} - \frac{26}{7} x + 18

\frac{182 + 2548 x - 12740}{26}, \frac{182 - 2548 x - 12740}{26}

Solution steps

y = \frac{13}{49} x^{2} - \frac{26}{7} x + 18

Replace

x

with

y

x = \frac{13}{49} y^{2} - \frac{26}{7} y + 18

Solve for

y, x = \frac{13}{49} y^{2} - \frac{26}{7} y + 18

\frac{182 + 2548 x - 12740}{26}, \frac{182 - 2548 x - 12740}{26}

\frac{2 x ^{2} + x - 18}{x ^{2} - 9}

y = - x^{2} + 2 x, x > - 1

f (x) = 2 (8) + 5

f (x) = \frac{2 x ^{2} - 5 x}{2}

h (x) = \frac{2}{3} x + 10

What is the inverse of 13/49 x^2-26/7 x+18 ?
The inverse of 13/49 x^2-26/7 x+18 is (182+sqrt(2548x-12740))/(26),(182-sqrt(2548x-12740))/(26)