What is the inverse of (sqrt(x)-7)/(x-49) ?

The inverse of (sqrt(x)-7)/(x-49) is (49x^2-14x+1)/(x^2)

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inverse of (sqrt(x)-7)/(x-49)

inverse

\frac{x - 7}{x - 49}

\frac{49 x ^{2} - 14 x + 1}{x ^{2}}

Solution steps

y = \frac{x - 7}{x - 49}

Replace

x

with

y

x = \frac{y - 7}{y - 49}

Solve for

y, x = \frac{y - 7}{y - 49}

\frac{49 x ^{2} - 14 x + 1}{x ^{2}}

\frac{x + 5}{x + 8}

f (x) = 6 (ln (x) - 4)

sin (\frac{12}{13})

y = lo g_{10} (3 x - 1)

2 cos (x), 0 \leq x \leq 2 π

What is the inverse of (sqrt(x)-7)/(x-49) ?
The inverse of (sqrt(x)-7)/(x-49) is (49x^2-14x+1)/(x^2)