What is the inverse of f(x)=(x^2+5)/5 ?

The inverse of f(x)=(x^2+5)/5 is sqrt(5x-5),-sqrt(5x-5)

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inverse of f(x)=(x^2+5)/5

inverse

f (x) = \frac{x ^{2} + 5}{5}

5 x - 5, - 5 x - 5

Solution steps

y = \frac{x ^{2} + 5}{5}

Replace

x

with

y

x = \frac{y ^{2} + 5}{5}

Solve for

y, x = \frac{y ^{2} + 5}{5}

5 x - 5, - 5 x - 5

\frac{- 77}{191}

4 x + 9 + 17

4^{x + 5}

f (x) = x - x^{2}

f (x) = f (2.44) = 15.72

What is the inverse of f(x)=(x^2+5)/5 ?
The inverse of f(x)=(x^2+5)/5 is sqrt(5x-5),-sqrt(5x-5)