What is the inverse of f(x)=(x-1)^2+6 ?

The inverse of f(x)=(x-1)^2+6 is sqrt(x-6)+1,-sqrt(x-6)+1

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inverse of f(x)=(x-1)^2+6

inverse

f (x) = (x - 1)^{2} + 6

x - 6 + 1, - x - 6 + 1

Solution steps

y = (x - 1)^{2} + 6

Replace

x

with

y

x = (y - 1)^{2} + 6

Solve for

y, x = (y - 1)^{2} + 6

x - 6 + 1, - x - 6 + 1

\frac{( z - 1 )}{( z - e ^{- 1} )}

f (x) = \frac{3 x}{5}

\frac{5 - e ^{- x}}{5 + e ^{- x}}

1 1^{x}

What is the inverse of f(x)=(x-1)^2+6 ?
The inverse of f(x)=(x-1)^2+6 is sqrt(x-6)+1,-sqrt(x-6)+1