What is the inverse of y= 64/25 x^2 ?

The inverse of y= 64/25 x^2 is (5sqrt(x))/8 ,-(5sqrt(x))/8

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inverse of y= 64/25 x^2

inverse

y = \frac{64}{25} x^{2}

\frac{5 x}{8}, - \frac{5 x}{8}

Solution steps

y = \frac{64}{25} x^{2}

Replace

x

with

y

x = \frac{64}{25} y^{2}

Solve for

y, x = \frac{64}{25} y^{2}

\frac{5 x}{8}, - \frac{5 x}{8}

f (x) = 0.5 x^{0.5}

f (x) = 5 x - 11 = - 36

f (x) = 18 - x^{2}

csc (2)

y = 1 0^{x} - \frac{3}{2}

What is the inverse of y= 64/25 x^2 ?
The inverse of y= 64/25 x^2 is (5sqrt(x))/8 ,-(5sqrt(x))/8