What is the inverse of f(x)= 1/4 (x+3)^2 ?

The inverse of f(x)= 1/4 (x+3)^2 is 2sqrt(x)-3,-2sqrt(x)-3

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inverse of f(x)= 1/4 (x+3)^2

inverse

f (x) = \frac{1}{4} (x + 3)^{2}

2 x - 3, - 2 x - 3

Solution steps

y = \frac{1}{4} (x + 3)^{2}

Replace

x

with

y

x = \frac{1}{4} (y + 3)^{2}

Solve for

y, x = \frac{1}{4} (y + 3)^{2}

2 x - 3, - 2 x - 3

3 - ln (7 x)

f (x) = - \frac{3}{2 x}

f (x) = \frac{x ( x - 3 )}{x - 4}

f (x) = - \frac{2}{5} (x - 2)^{3} - 4

y = 3 (2)^{x} + 1

What is the inverse of f(x)= 1/4 (x+3)^2 ?
The inverse of f(x)= 1/4 (x+3)^2 is 2sqrt(x)-3,-2sqrt(x)-3