What is the inverse of y=(9x^3+2)/(-2x^3+3) ?

The inverse of y=(9x^3+2)/(-2x^3+3) is -\sqrt[3]{(2-3x)/(9+2x)}

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inverse of y=(9x^3+2)/(-2x^3+3)

inverse

y = \frac{9 x ^{3} + 2}{- 2 x ^{3} + 3}

Solution steps

y = \frac{9 x ^{3} + 2}{- 2 x ^{3} + 3}

Replace

x

with

y

x = \frac{9 y ^{3} + 2}{- 2 y ^{3} + 3}

Solve for

y, x = \frac{9 y ^{3} + 2}{- 2 y ^{3} + 3}

f (x) = \frac{ln ( \frac{x}{34} )}{0.003}

f (y) = y - y^{2}

f (x) = - x^{2} + 3 x - 2, x = - 2

2 π (x)^{2} + 8 π (x)

f (x) = - 5000 x + 60000

What is the inverse of y=(9x^3+2)/(-2x^3+3) ?
The inverse of y=(9x^3+2)/(-2x^3+3) is -\sqrt[3]{(2-3x)/(9+2x)}