What is the inverse of f(x)=((x-7))/((x+4)) ?

The inverse of f(x)=((x-7))/((x+4)) is (-7-4x)/(x-1)

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inverse of f(x)=((x-7))/((x+4))

inverse

f (x) = \frac{( x - 7 )}{( x + 4 )}

\frac{- 7 - 4 x}{x - 1}

Solution steps

y = \frac{x - 7}{x + 4}

Replace

x

with

y

x = \frac{y - 7}{y + 4}

Solve for

y, x = \frac{y - 7}{y + 4}

\frac{- 7 - 4 x}{x - 1}

6 + 5 x - 5

f (x) = - \frac{1}{2} lo g_{5} (\frac{1}{x + 3})

\frac{10}{( t + 16 ) ( t + 25 )}

f (x) = - x^{2} - 4, x < 0

y (X) = \frac{2 X + 3}{5 - X}

What is the inverse of f(x)=((x-7))/((x+4)) ?
The inverse of f(x)=((x-7))/((x+4)) is (-7-4x)/(x-1)