What is the inverse of f(x)=(3x-1)/(4x+5) ?

The inverse of f(x)=(3x-1)/(4x+5) is (-1-5x)/(4x-3)

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inverse of f(x)=(3x-1)/(4x+5)

inverse

f (x) = \frac{3 x - 1}{4 x + 5}

\frac{- 1 - 5 x}{4 x - 3}

Solution steps

y = \frac{3 x - 1}{4 x + 5}

Replace

x

with

y

x = \frac{3 y - 1}{4 y + 5}

Solve for

y, x = \frac{3 y - 1}{4 y + 5}

\frac{- 1 - 5 x}{4 x - 3}

f (x) = 2 x - (\frac{4}{3})

f (x) = (x - 14)^{2}, [14, \infty]

\frac{s ^{2}}{s ^{2} + 1}

f (x) = \frac{- 5 x + 4}{3 x - 1}

f (x) = \frac{5}{2} x - \frac{15}{2}

What is the inverse of f(x)=(3x-1)/(4x+5) ?
The inverse of f(x)=(3x-1)/(4x+5) is (-1-5x)/(4x-3)