What is the inverse of f(x)=((x^2-4))/(2x^2) ?

The inverse of f(x)=((x^2-4))/(2x^2) is sqrt(-4/(2x-1)),-sqrt(-4/(2x-1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=((x^2-4))/(2x^2)

inverse

f (x) = \frac{( x ^{2} - 4 )}{2 x ^{2}}

- \frac{4}{2 x - 1}, - - \frac{4}{2 x - 1}

Solution steps

y = \frac{x ^{2} - 4}{2 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 4}{2 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 4}{2 y ^{2}}

- \frac{4}{2 x - 1}, - - \frac{4}{2 x - 1}

(6)^{\frac{1}{2}}

g (x) = - \frac{3}{4} x^{2} - \frac{1}{2}

(x - 1)^{4} + 3, x \geq 1

f (x) = \frac{5 x - 2}{4 x + 7}

f (x) = - 6 x^{5} + 17

What is the inverse of f(x)=((x^2-4))/(2x^2) ?
The inverse of f(x)=((x^2-4))/(2x^2) is sqrt(-4/(2x-1)),-sqrt(-4/(2x-1))