What is the inverse of f(x)=4a^2-5a+1 ?

The inverse of f(x)=4a^2-5a+1 is (5+sqrt(16a+9))/8 ,(5-sqrt(16a+9))/8

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inverse of f(x)=4a^2-5a+1

inverse

f (x) = 4 a^{2} - 5 a + 1

\frac{5 + 16 a + 9}{8}, \frac{5 - 16 a + 9}{8}

Solution steps

y = 4 a^{2} - 5 a + 1

Replace

a

with

y

a = 4 y^{2} - 5 y + 1

Solve for

y, a = 4 y^{2} - 5 y + 1

\frac{5 + 16 a + 9}{8}, \frac{5 - 16 a + 9}{8}

f (x) = (5 - (\frac{x}{4}))

f (- 1) = x^{2} - 2 x + 4

9 x + 1

1 - e^{- a x}

f (x) = \frac{x ^{2} + 4 x - 12}{x ^{2} - 9 x + 14}

What is the inverse of f(x)=4a^2-5a+1 ?
The inverse of f(x)=4a^2-5a+1 is (5+sqrt(16a+9))/8 ,(5-sqrt(16a+9))/8