What is the inverse of (x/(x+6))^2 ?

The inverse of (x/(x+6))^2 is (6(-x+sqrt(x)))/(x-1),-(6(x+sqrt(x)))/(x-1)

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inverse of (x/(x+6))^2

inverse

(\frac{x}{x + 6})^{2}

\frac{6 ( - x + x )}{x - 1}, - \frac{6 ( x + x )}{x - 1}

Solution steps

y = (\frac{x}{x + 6})^{2}

Replace

x

with

y

x = (\frac{y}{y + 6})^{2}

Solve for

y, x = (\frac{y}{y + 6})^{2}

\frac{6 ( - x + x )}{x - 1}, - \frac{6 ( x + x )}{x - 1}

y = \frac{2 x + 9}{x - 5}

10 - 2 x + 3 x - 1

\frac{x}{3}

f (x) = \frac{( 1 - 3 x )}{( 2 x + 1 )}

lo g_{e} ((cos (x))^{2})

What is the inverse of (x/(x+6))^2 ?
The inverse of (x/(x+6))^2 is (6(-x+sqrt(x)))/(x-1),-(6(x+sqrt(x)))/(x-1)