What is the inverse of f(x)=((1-3x))/((2x+1)) ?

The inverse of f(x)=((1-3x))/((2x+1)) is (1-x)/(2x+3)

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inverse of f(x)=((1-3x))/((2x+1))

inverse

f (x) = \frac{( 1 - 3 x )}{( 2 x + 1 )}

\frac{1 - x}{2 x + 3}

Solution steps

y = \frac{1 - 3 x}{2 x + 1}

Replace

x

with

y

x = \frac{1 - 3 y}{2 y + 1}

Solve for

y, x = \frac{1 - 3 y}{2 y + 1}

\frac{1 - x}{2 x + 3}

lo g_{e} ((cos (x))^{2})

f (x) = x^{3} - 1, x > \frac{π}{2}

y = x + 1

f (x) = \frac{( - 4 x - 2 )}{( - 3 x + 2 )}

\frac{x + 6}{x + 2}

What is the inverse of f(x)=((1-3x))/((2x+1)) ?
The inverse of f(x)=((1-3x))/((2x+1)) is (1-x)/(2x+3)