What is the inverse of y=2pix^2+16pix ?

The inverse of y=2pix^2+16pix is (-16pi+sqrt(256pi^2+8pix))/(4pi),(-16pi-sqrt(256pi^2+8pix))/(4pi)

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inverse of y=2pix^2+16pix

inverse

y = 2 π x^{2} + 16 π x

\frac{- 16 π + 256 π ^{2} + 8 π x}{4 π}, \frac{- 16 π - 256 π ^{2} + 8 π x}{4 π}

Solution steps

y = 2 π x^{2} + 16 π x

Replace

x

with

y

x = 2 π y^{2} + 16 π y

Solve for

y, x = 2 π y^{2} + 16 π y

\frac{- 16 π + 256 π ^{2} + 8 π x}{4 π}, \frac{- 16 π - 256 π ^{2} + 8 π x}{4 π}

f (x) = \frac{x + 1}{2 ( x )}

\frac{s - 4}{s ^{2} - 2 s + 9}

f (x) = \frac{5 x}{9 - 7 x}

f (x) = lo g_{10} (3) (x - 1) + 2

What is the inverse of y=2pix^2+16pix ?
The inverse of y=2pix^2+16pix is (-16pi+sqrt(256pi^2+8pix))/(4pi),(-16pi-sqrt(256pi^2+8pix))/(4pi)