What is the inverse of cos((-9)/(sqrt(161))) ?

The inverse of cos((-9)/(sqrt(161))) is None

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of cos((-9)/(sqrt(161)))

inverse

cos (\frac{- 9}{161})

None

Solution steps

cos (a) = b \Rightarrow a = arccos (b)

\frac{- 9}{161} = arccos (y)

Solve for

x, \frac{- 9}{161} = arccos (y)

Since the function is a constant function it has no inverse function

None

f (x) = - 2 e^{x} + 1

g (x) = \frac{x + 4}{1 - x}

f (x) = (\frac{- ( cos ( π \cdot y ) - 1 )}{2})

- 4 x - 3

- 4 x - 2

What is the inverse of cos((-9)/(sqrt(161))) ?
The inverse of cos((-9)/(sqrt(161))) is None