What is the inverse of f(x)=-0.1x^2+90 ?

The inverse of f(x)=-0.1x^2+90 is sqrt(-10x+900),-sqrt(-10x+900)

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inverse of f(x)=-0.1x^2+90

inverse

f (x) = - 0.1 x^{2} + 90

- 10 x + 900, - - 10 x + 900

Solution steps

y = - 0.1 x^{2} + 90

Replace

x

with

y

x = - 0.1 y^{2} + 90

Solve for

y, x = - 0.1 y^{2} + 90

- 10 x + 900, - - 10 x + 900

f (x) = - \frac{1}{2} (\frac{1}{2})^{x} + 7

f (x) = arccos (e) (e^{3 x})

\frac{4}{a - 7}

- \frac{( 2 x + 3 )}{x} - 5

f (x) = (ln (x))^{6}

What is the inverse of f(x)=-0.1x^2+90 ?
The inverse of f(x)=-0.1x^2+90 is sqrt(-10x+900),-sqrt(-10x+900)