What is the inverse of f(x)=2(x-1)^2+4 ?

The inverse of f(x)=2(x-1)^2+4 is sqrt((x-4)/2)+1,-sqrt((x-4)/2)+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2(x-1)^2+4

inverse

f (x) = 2 (x - 1)^{2} + 4

\frac{x - 4}{2} + 1, - \frac{x - 4}{2} + 1

Solution steps

y = 2 (x - 1)^{2} + 4

Replace

x

with

y

x = 2 (y - 1)^{2} + 4

Solve for

y, x = 2 (y - 1)^{2} + 4

\frac{x - 4}{2} + 1, - \frac{x - 4}{2} + 1

f (x) = 4 - x + 10

f (x) = 2^{\frac{1}{x}}, x > 0

f (x) = 2 (x - 1)^{2} - 4

(x + 3)^{2} - 4

1.1

What is the inverse of f(x)=2(x-1)^2+4 ?
The inverse of f(x)=2(x-1)^2+4 is sqrt((x-4)/2)+1,-sqrt((x-4)/2)+1