What is the inverse of f(x)=(2x-7)^2-9 ?

The inverse of f(x)=(2x-7)^2-9 is (sqrt(x+9)+7)/2 ,(-sqrt(x+9)+7)/2

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inverse of f(x)=(2x-7)^2-9

inverse

f (x) = (2 x - 7)^{2} - 9

\frac{x + 9 + 7}{2}, \frac{- x + 9 + 7}{2}

Solution steps

y = (2 x - 7)^{2} - 9

Replace

x

with

y

x = (2 y - 7)^{2} - 9

Solve for

y, x = (2 y - 7)^{2} - 9

\frac{x + 9 + 7}{2}, \frac{- x + 9 + 7}{2}

800 x - 2 x^{2}

f (x) = \frac{3 x}{( 7 x ^{2} + 16 )}

y = (e)^{x}

1 (0.5)^{x}

e^{- \frac{x ^{4}}{2}}

What is the inverse of f(x)=(2x-7)^2-9 ?
The inverse of f(x)=(2x-7)^2-9 is (sqrt(x+9)+7)/2 ,(-sqrt(x+9)+7)/2