What is the domain of f(x)=sqrt((x+2)/(x^2-9)) ?

The domain of f(x)=sqrt((x+2)/(x^2-9)) is -3 3

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domain of f(x)=sqrt((x+2)/(x^2-9))

domain

f (x) = \frac{x + 2}{x ^{2} - 9}

- 3 < x \leq - 2 or x > 3

Interval Notation

(- 3, - 2] \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

- 3 < x \leq - 2 or x > 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x \leq - 2 or x > 3

f (x) = \frac{8 x + 5}{2 - 5 x}

f (x) = \frac{8 x + 5}{4 x + 2}

f (x) = lo g_{2} (2 x - \frac{1}{2})

g (x) = x^{2} - 4 x

f (x) = 6 x^{2} + 500 x + 8000

What is the domain of f(x)=sqrt((x+2)/(x^2-9)) ?
The domain of f(x)=sqrt((x+2)/(x^2-9)) is -3<x<=-2\lor x>3