What is the domain of f(x)=(x-5)/(x^2-4x) ?

The domain of f(x)=(x-5)/(x^2-4x) is x 4

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domain of f(x)=(x-5)/(x^2-4x)

domain

f (x) = \frac{x - 5}{x ^{2} - 4 x}

x < 0 or 0 < x < 4 or x > 4

Interval Notation

(- \infty, 0) \cup (0, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = 0

The function domain

x < 0 or 0 < x < 4 or x > 4

f (x) = lo g_{2} (6 - 2 x)

f (x) = \frac{cos ( 2 x )}{cos ( x ) - sin ( x )}

x - \frac{4}{x}

f (x) = lo g_{5} (3 x^{2} - 5 x + 2)

f (x) = x + a

What is the domain of f(x)=(x-5)/(x^2-4x) ?
The domain of f(x)=(x-5)/(x^2-4x) is x<0\lor 0<x<4\lor x>4