What is the domain of f(x)=sin^2(sqrt(x)) ?

The domain of f(x)=sin^2(sqrt(x)) is x>= 0

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domain of f(x)=sin^2(sqrt(x))

domain

f (x) = sin^{2} (x)

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = \frac{3 x - 2 - x ^{2}}{2 x - 4}

f (x) = \frac{4 x + 3}{2 x - 1}

f (x) = - \frac{2}{5} x + 6

f (x) = (\frac{1}{3})^{x} + 1

f (x) = \frac{9 x - 4}{4 x + 8}

What is the domain of f(x)=sin^2(sqrt(x)) ?
The domain of f(x)=sin^2(sqrt(x)) is x>= 0