What is the domain of f(x)=log_{1/5}(x^2-x-12)+6 ?

The domain of f(x)=log_{1/5}(x^2-x-12)+6 is x 4

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domain of f(x)=log_{1/5}(x^2-x-12)+6

domain

f (x) = lo g_{\frac{1}{5}} (x^{2} - x - 12) + 6

x < - 3 or x > 4

Interval Notation

(- \infty, - 3) \cup (4, \infty)

Solution steps

Find positive values for logs:

x < - 3 or x > 4

The function domain

x < - 3 or x > 4

\frac{9 x - 4}{4 x + 8}

y = \frac{x ^{3}}{- x ^{2} + 4}

f (x) = lo g_{4} (5 x - 9)

\frac{x + 2}{x ^{2} - 9}

f (x) = \frac{3 - x}{x ^{2} - 4}

What is the domain of f(x)=log_{1/5}(x^2-x-12)+6 ?
The domain of f(x)=log_{1/5}(x^2-x-12)+6 is x<-3\lor x>4